(-952w+2w^2)=0

Solution for (-952w+2w^2)=0 equation:

(-952w+2w^2)=0

We get rid of parentheses

2w^2-952w=0

a = 2; b = -952; c = 0;
Δ = b2-4ac
Δ = -9522-4·2·0
Δ = 906304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{906304}=952$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-952)-952}{2*2}=\frac{0}{4}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-952)+952}{2*2}=\frac{1904}{4}
=476
$